![[align=center][img]http://img64.imageshack.us/img64/9004/katangahan.png[/img] ------------------------------------------------------------------------------------------------- [b]FOR THE RULES & RERGU](t49497-p1679-%255Balign%253Dcenter%255D%255Bimg%255Dhttp%253A%252F%252Fimg64.imageshack.us%252Fimg64%252F9004%252Fkatangahan.png%255B%252Fimg%255D%250A-------------------------------------------------------------------------------------------------%250A%255Bb%255DFOR%2BTHE%2BRULES%2B%2526%2BRERGU.html#p3674375){kind=link}
[align=center][img]http://img64.imageshack.us/img64/9004/katangahan.png[/img] ------------------------------------------------------------------------------------------------- [b]FOR THE RULES & RERGU
You are viewing a post by m4ndz9. View all 33689 posts in [align=center][img]http://img64.imageshack.us/img64/9004/katangahan.png[/img] ------------------------------------------------------------------------------------------------- [b]FOR THE RULES & RERGU.
2010-09-11 17:09:17
- m4ndz9
- » FTalkFreak
1581
0
1969-12-31
Re: [align=center][img]http://img64.imageshack.us/img64/9004/katangahan.png[/img] ------------------------------------------------------------------------------------------------- [b]FOR THE RULES & RERGU
[quote=xxBUBBLiExx;#3674373;1284238602]kailangan ba yung restrictions?[/quote]
anong restrictions?
[quote=xxBUBBLiExx;#3674374;1284238919]f(x)/g(x) = (3x+4)/(2x-1)
if x = 1/2, f(x)/g(x) is undefined
if x ≠ 1/2, f(x)/g(x) = (3x+4)/(2x-1)
f(x)/g(x) = (3x+4)/(2x-1) , {x | x≠1/2}[/quote]
saan ba galing yung 1/2?
 |