[quote=sugarstyx_x]:idea: PLEASE READ: � You're not allowed to Plagiarize, we do not encourage this. � Members can help you but not allowed to do the work for you. � This is a Discussion thread
You are viewing a post by cfreng2. View all 386 posts in [quote=sugarstyx_x]:idea: PLEASE READ: � You're not allowed to Plagiarize, we do not encourage this. � Members can help you but not allowed to do the work for you. � This is a Discussion thread .
2008-09-30 06:06:40
- cfreng2
- » FTalkAddict
335
0
1969-12-31
Re: [quote=sugarstyx_x]:idea: PLEASE READ: � You're not allowed to Plagiarize, we do not encourage this. � Members can help you but not allowed to do the work for you. � This is a Discussion thread
[quote=xPEPPERMINTx]find y'
y = sin(3x - 2)[/quote]
let t
x-2 dt = 3dx
y=sint
dy=cos(t)dt
substituting t= 3x-2 and dt = 3dx
dy =cos(3x-2)(3dx)
dy/dx=y'=3cos(3x-2)
Therefore, y'=3cos(3x-2)
Hope it helped!
x-2 dt = 3dx
y=sint
dy=cos(t)dt
substituting t= 3x-2 and dt = 3dx
dy =cos(3x-2)(3dx)
dy/dx=y'=3cos(3x-2)
Therefore, y'=3cos(3x-2)
Hope it helped!
 |